# Visible light falls into wavelength ranges of 400-700 nm, for which

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### Visible light falls into wavelength ranges of 400-700 nm, for which 1 m=1Ã—109 nm1 m=1Ã—109 nm. The energy and wavelength of light are related by the equation E=hc/Î»where E is energy in Joules, h is Planck's constant (6.626Ã—10âˆ’34 J-s6.626Ã—10âˆ’34 J-s ), c is the speed of light ( 2.998Ã—108 m/s2.998Ã—108 m/s ), and Î» is the wavelength in m. If a visible light photon has a wavelength of 669.8 nm, what is the energy of the photon (in J)?

**The Correct Answer is**

**2.966e-19Convert the wavelength from nanometers to meters using the relationship that1 m=1Ã—109 nm. Î» in m=669.8 nmÃ—(1 m/1Ã—109 nm)Then substitute the wavelength into the equation.E=hc/Î»=(6.626Ã—10âˆ’34 J-s)(2.998Ã—108 m/s)/ Î» in m**

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