Two equal-magnitude forces are applied to a door at the doorknob. The first force is applied perpendicular to the door, and the second force is applied at 30° to the plane of the door. Which force exerts the greater torque about the door hinge?

By: Answerout


Here is the answer for the question - Two equal-magnitude forces are applied to a door at the doorknob. The first force is applied perpendicular to the door, and the second force is applied at 30° to the plane of the door. Which force exerts the greater torque about the door hinge?. You'll find the correct answer below

Two equal-magnitude forces are applied to a door at the doorknob. The first force is applied perpendicular to the door, and the second force is applied at 30° to the plane of the door. Which force exerts the greater torque about the door hinge? -Both forces exert zero torque. -the first force (applied perpendicular to the door) -the second force (applied at an angle) -Both forces exert equal non-zero torques.

The Correct Answer is

the first force (applied perpendicular to the door)

Reason Explained

the first force (applied perpendicular to the door) is correct for Two equal-magnitude forces are applied to a door at the doorknob. The first force is applied perpendicular to the door, and the second force is applied at 30° to the plane of the door. Which force exerts the greater torque about the door hinge?

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